x^2+20x-36000=0

Solution for x^2+20x-36000=0 equation:

x^2+20x-36000=0

a = 1; b = 20; c = -36000;
Δ = b2-4ac
Δ = 202-4·1·(-36000)
Δ = 144400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144400}=380$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-380}{2*1}=\frac{-400}{2}
=-200
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+380}{2*1}=\frac{360}{2}
=180
$